Turbo Physics Grade 12 Pdf [ VALIDATED · TUTORIAL ]

T₂ = 298 K × (1.8/1.0)^0.286 T₂ = 298 × 1.8^0.286 1.8^0.286 ≈ 1.178 T₂ ≈ 351 K → 78°C (theoretical ideal).

At 1.8 atm and 135°C (408 K): ρ = (1.8 × 101325 Pa) / (287 J/kg·K × 408 K) ρ ≈ 182385 / 117096 ≈ 1.56 kg/m³ turbo physics grade 12 pdf

At steady state, Power_turbine × η_mech = Power_compressor T₂ = 298 K × (1

T₂ = 298 K × (1.8/1.0)^0.286 T₂ = 298 × 1.8^0.286 1.8^0.286 ≈ 1.178 T₂ ≈ 351 K → 78°C (theoretical ideal).

At 1.8 atm and 135°C (408 K): ρ = (1.8 × 101325 Pa) / (287 J/kg·K × 408 K) ρ ≈ 182385 / 117096 ≈ 1.56 kg/m³

At steady state, Power_turbine × η_mech = Power_compressor

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