Titrasi Asam Basa Contoh Soal May 2026

[ M_a V_a \times n_a = M_b V_b \times n_b ] [ (0.250)(V_a)(2) = (0.100)(50.0)(1) ] [ 0.500 , V_a = 5.00 ] [ V_a = 10.0 , mL ]

Reaction: ( H_2SO_4 + 2KOH \rightarrow K_2SO_4 + 2H_2O ) Here, ( n_a = 2 ) (H₂SO₄ gives 2 H⁺), ( n_b = 1 ) (KOH gives 1 OH⁻). titrasi asam basa contoh soal

pOH = (-\log(5.27 \times 10^-6) = 5.28) pH = (14 - 5.28 = 8.72) [ M_a V_a \times n_a = M_b V_b \times n_b ] [ (0

10.0 mL of H₂SO₄ Problem 3: Finding Molar Mass of Unknown Acid (Advanced) Question: A 0.200 g sample of an unknown monoprotic acid (HA) is titrated with 0.100 M NaOH. The equivalence point is reached after adding 25.0 mL of NaOH. What is the molar mass of the acid? What is the molar mass of the acid

At equivalence, moles of acid = moles of base = (0.0500 , L \times 0.100 , M = 0.00500 , mol) Total volume = (50.0 + 50.0 = 100.0 , mL = 0.100 , L) Concentration of conjugate base (A⁻) = (0.00500 / 0.100 = 0.0500 , M)

[ M_acid V_acid = M_base V_base ] [ (0.100 , M)(25.0 , mL) = M_base (20.0 , mL) ] [ M_base = \frac2.5020.0 = 0.125 , M ]