Integral Calculus Reviewer By Ricardo Asin Pdf 54 May 2026

So bracket = (\frac27\pi4 + 9).

First integral: (\int \sqrt9-y^2, dy) is a standard semicircle area formula. From (y=-3) to (0), it’s a quarter circle of radius 3. Area of quarter circle = (\frac14\pi (3^2) = \frac9\pi4). So (3 \times \frac9\pi4 = \frac27\pi4). Integral Calculus Reviewer By Ricardo Asin Pdf 54

Weight of the slice = volume × density of water (1000 kg/m³ × 9.8 m/s² = 9800 N/m³): [ dF = 9800 \cdot 20\sqrt9-y^2 , dy = 196000\sqrt9-y^2 , dy \quad \text(Newtons). ] So bracket = (\frac27\pi4 + 9)