Gre Math Prep Questions -

Emily thought for a moment and then solved the problem. She calculated the total revenue as 250 loaves x $2 = $500, and the total cost as 250 loaves x $0.50 = $125. Then, she subtracted the cost from the revenue to get the profit: $500 - $125 = $375.

One day, while practicing, Emily came across a question that made her scratch her head: gre math prep questions

A function f(x) = 2x^2 + 3x - 4 is defined for all real numbers. If f(x) = 5, what are the values of x? Emily thought for a moment and then solved the problem

Emily set up the equation: 2x^2 + 3x - 4 = 5. She rearranged the equation to get 2x^2 + 3x - 9 = 0. Using the quadratic formula, she solved for x: x = (-b ± √(b^2 - 4ac)) / 2a. Plugging in the values, she got x = (-(3) ± √((3)^2 - 4(2)(-9))) / (2(2)). After some algebra, she got two solutions: x = 1.5 and x = -3. One day, while practicing, Emily came across a

If a bakery sells 250 loaves of bread per day at $2 each, and each loaf costs $0.50 to produce, what is the bakery's daily profit?

Emily recalled the Capital Asset Pricing Model (CAPM) formula: E(R) = Rf + β(E(Rm) - Rf). She plugged in the values and solved for E(Rm): 10% = 4% + 1.2(E(Rm) - 4%). After some algebra, she got E(Rm) = 8.33%.